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I'm looking for a crochet graph pattern of Pattern Graph the Carolina Hurricanes NHL team, can you help me find it?
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20 Responses to “Pattern Graph Review”
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January 3rd, 2011 at 5:25 pm
line of best fit
January 4th, 2011 at 5:42 am
see the Pearson’s chi square test
January 4th, 2011 at 5:12 pm
Are you talking about knitting? Sewing? Cross Stitch?Generally speaking, you count squares on the graph. If your graph is to scale, then one square is one stitch. if your graph is half scale, then on square is two stitches, and so on..
January 5th, 2011 at 5:50 am
Do you have a copy of their logo? If you do get some graph paper and make it for yourself if you cannot find it anywhere else.
January 5th, 2011 at 5:55 pm
take a look at x values and determine if x values are growing/decreasing by a constantdo the same for y valuesonly if both x and y are growing/decreasing by a constant do you have a linear relationshipfor example:x: 1 2 3 4 5 y: -3 -1 1 3 5x is increasing by 1 and y is increasing by 2 so it is a linear relationshiphowever,x: 1 2 3 4 5 y: 1 2 4 8 10here x is increasing by 1 by y is growing by a factor of 2 so it is not a linear relationship
January 6th, 2011 at 5:52 am
With all due respect to the previous answer, the requirement for exponential decay is that the rate of decay is governed by the equationdx/dt = -kx, which integrates tox = x₀ exp(-kt), where x₀ is the value of x at t = 0.Taking the logarithm of both sides,ln(x) = ln(x₀) – ktTo the table of values, add an additional column for ln(x). For example:_t__ _x_ ln(x)_0.00 100. 4.610.01 81.9 4.410.02 67.0 4.200.03 54.8 4.000.04 44.9 3.80The constant k, if the relationship is exponential, will be-k = change in ln(x) / change in tLet’s try for the first two rows of the table:-k₀₁ = ∆ ln(x) / ∆t = (4.41-4.61)/(0.01-0) = 20and continuing,-k₁₂ = (4.41-4.20)/(.02-.01) = 21-k₂₃ = (4.20-4.00)/(.03-.02) = 20-k₃₄ = (4.00-3.80)/(.04-.03) = 20The data, incidentally, will rarely yield k-values as constant as these are.Plotting is faster than doing the above calculations. If you plot ln(x) versus t, the data will lie in a straight line if the relationship is exponential, and the slope is obtained as we did above, selecting not a data pair, but the ln(x) and t values at two different, well-separated, points on the line.Of course, if the equation can be manipulated into eitherx = x₀ exp(-kt) or ln(x) = ln(x₀) – kt,then the relationship is exponential.For an exponential increase, incidentally, all of the above is true with +k substituted for -k.
January 6th, 2011 at 5:48 pm
If it does not go up by a constant amount, then it is not linear. If it does, then it is linear and easy to do. Use rise over run to figure out slope, and then use the slope you found and this equation to find the y-intercept:y – y1= m (x-x1), where m is your slope, and (x1,y1) is any point on the line. Solve by getting the y by itself.
January 7th, 2011 at 5:49 am
RAIDERS BABY!!! JUST WIN BABY!!!
January 7th, 2011 at 5:51 pm
this site says they have it …
January 8th, 2011 at 5:19 am
http://www.crochetedjustforyou.com/FootballPatterns.html
January 8th, 2011 at 5:02 pm
Here are some cute ideas for teddy’s head, I especially like the mouse head for a good shape. I did do a bunny with a cute head, the back was just round, but the front was in three pieces, a triangle for the forehead to nose, and 2 side pieces. the finished product was wicked cute. I kind of made it up with paper, so i do not have the pattern.
January 9th, 2011 at 5:51 am
It sounds like we need to find the least common multiple. Since lcm works on integers, we can write all numbers as fractions with denominator 10: 10= ((100)/(10)) 9.4= ((94)/(10)) 8.3= ((83)/(10)) 7.6= ((76)/(10)) 6.9= ((69)/(10)) 5.7= ((57)/(10)) 4.3= ((43)/(10)) 3.8= ((38)/(10)) 2.6= ((26)/(10)) 1.5= ((15)/(10))Now we compute lcm of the numerators knowing that the result will be in 1/10:lcm(15,26,38,43,57,69,76,83,94,100)= 285 884394900
January 9th, 2011 at 5:02 pm
The patter of data in a graph is if the graph is going down or up at a specific rate like slope….Like lets say ur looking at a graph of ur grade per week. The pattern would be that every week ur grades go up (lets say) 0.50 points
January 10th, 2011 at 5:02 am
I assuming you mean the standard equation for a parabola.y = a(x – h)^2 + hThe vertex is given by (h, k) and a is the vertcal stretch of the parabola. Usually, they are given in different form, though.y = [1/(4p)](x – k)^2 + kWhich you can easily derive the focus which is (h, k + p) and the directix at y = k – p.EDIT:To answer your additonal details, adding/subtracting to h will cause it to move to the right/left and adding/subtracting to k will cause it to move up/down. Like I said before, the value of a changes the vertical stretch. If |a| < 1, it will be narrower than x^2, if |a| > 1, it will be wider. If a < 0, the parabola will be up-side down.Hope this helps!
January 10th, 2011 at 5:26 pm
I wasnt able to find an exact answer for you. I have no idea why the rabbit ileum makes such a good experimental target in comparison to other animals. It does seem to be a very popular target of experimental research however.If you are looking for a picture of a graph however, check out figure 1 and 3 on this link.http://www.nature.com/bjp/journal/v127/n3/full/0702594a.html
January 11th, 2011 at 5:10 am
You need a curve fitting program such as datafit 9.google datafit…
January 11th, 2011 at 5:17 pm
Plot the pairs of numbers. The first number is just 0, 1, 2, 3, etc. The second number is the next number in the Fibonacci sequence.x, y(0, 1)(1, 1)(2, 2)(3, 3)(4, 5)(5, 8)(6, 13)(7, 21)(8, 34)(9, 55)(10, 89)(11, 144)etc.Then connect the points with lines. It should look like an upward curve. See the attached link.
January 12th, 2011 at 5:01 am
B. The U.S. economy suffered a number of negative supply shocks during the 1970s.Negative supply shocks created higher expected inflation (assuming more adaptive expectations) – which shifted Philips curve up.
January 12th, 2011 at 5:15 pm
i would use a bar graph for each color of m&m. or you could try making one long bar graph that goes from 0 to the total # of m&m’s in the bag. then color each part of the bar according to how many colored m&m’s there are.
January 13th, 2011 at 5:36 am
if your graphing a single thing, like temperature on the bottom and time on the side for example, then use a bar graph. because over time the temperature will rise.a scatter plot is used for a bunch of individual things and stuff. like students at a school and their lunch money. like X amounts of students, scattrered depending on their amount of money… ive never really used these since like middle school or elementary school. especially in a science class.